What is the general solution for cos(A)= 12/37 ?

The general solution for cos(A)= 12/37 is A=1.24049…+2pin,A=2pi-1.24049…+2pin

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cos(A)= 12/37

cos (A) = \frac{12}{37}

A = 1.24049 \dots + 2 πn, A = 2 π - 1.24049 \dots + 2 πn

Solution steps

cos (A) = \frac{12}{37}

Apply trig inverse properties

A = arccos (\frac{12}{37}) + 2 πn, A = 2 π - arccos (\frac{12}{37}) + 2 πn

Show solutions in decimal form

A = 1.24049 \dots + 2 πn, A = 2 π - 1.24049 \dots + 2 πn

2 \cdot sin^{2} (θ) = 3 (1 - cos (θ))

(sin (2 x) + cos (2 x))^{2} = 2

1.5 = 6 sin (x)

\frac{2 sin ( x ) - 1}{3 \cdot cos ( x )} = 0

tan (θ) = \frac{34400}{254}

What is the general solution for cos(A)= 12/37 ?
The general solution for cos(A)= 12/37 is A=1.24049…+2pin,A=2pi-1.24049…+2pin