What is the general solution for 4cos(x-1)=0 ?

The general solution for 4cos(x-1)=0 is x= pi/2+2pin+1,x=(3pi)/2+2pin+1

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4cos(x-1)=0

4 cos (x - 1) = 0

x = \frac{π}{2} + 2 πn + 1, x = \frac{3 π}{2} + 2 πn + 1

Solution steps

4 cos (x - 1) = 0

Divide both sides by

4

cos (x - 1) = 0

General solutions for

cos (x - 1) = 0

x - 1 = \frac{π}{2} + 2 πn, x - 1 = \frac{3 π}{2} + 2 πn

Solve

x - 1 = \frac{π}{2} + 2 πn : x = \frac{π}{2} + 2 πn + 1

Solve

x - 1 = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{2} + 2 πn + 1

x = \frac{π}{2} + 2 πn + 1, x = \frac{3 π}{2} + 2 πn + 1

cos (θ) = \frac{5}{7}, cos (\frac{θ}{2}), 0^{\circ} < θ < 9 0^{\circ}

sin (x) + 4 = cos (x) + 3

\frac{sin ( 17 0 ^{\circ} )}{8} = \frac{sin ( B )}{5}

tan (x) = 0.01096

3 - 2 csc (x) = 17

What is the general solution for 4cos(x-1)=0 ?
The general solution for 4cos(x-1)=0 is x= pi/2+2pin+1,x=(3pi)/2+2pin+1