What is the general solution for sin(2x+pi/3)=0 ?

The general solution for sin(2x+pi/3)=0 is x=pin-pi/6 ,x=pin+pi/2-pi/6

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sin(2x+pi/3)=0

sin (2 x + \frac{π}{3}) = 0

x = πn - \frac{π}{6}, x = πn + \frac{π}{2} - \frac{π}{6}

Solution steps

sin (2 x + \frac{π}{3}) = 0

General solutions for

sin (2 x + \frac{π}{3}) = 0

2 x + \frac{π}{3} = 0 + 2 πn, 2 x + \frac{π}{3} = π + 2 πn

Solve

2 x + \frac{π}{3} = 0 + 2 πn : x = πn - \frac{π}{6}

Solve

2 x + \frac{π}{3} = π + 2 πn : x = πn + \frac{π}{2} - \frac{π}{6}

x = πn - \frac{π}{6}, x = πn + \frac{π}{2} - \frac{π}{6}

300 = \frac{1}{32} 10 0^{2} sin (2 x)

sin^{2} (x) = \frac{45}{52}

2 cos^{2} (x) - 2 sin^{2} (x) = 3

\frac{π ^{2}}{8} sec^{2} (\frac{π x}{4}) tan (\frac{π x}{4}) = 0

sec (x) = \frac{2}{3}

What is the general solution for sin(2x+pi/3)=0 ?
The general solution for sin(2x+pi/3)=0 is x=pin-pi/6 ,x=pin+pi/2-pi/6