What is the general solution for 2cos(4x)=0 ?

The general solution for 2cos(4x)=0 is x= pi/8+(pin)/2 ,x=(3pi)/8+(pin)/2

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2cos(4x)=0

2 cos (4 x) = 0

x = \frac{π}{8} + \frac{πn}{2}, x = \frac{3 π}{8} + \frac{πn}{2}

Solution steps

2 cos (4 x) = 0

Divide both sides by

2

cos (4 x) = 0

General solutions for

cos (4 x) = 0

4 x = \frac{π}{2} + 2 πn, 4 x = \frac{3 π}{2} + 2 πn

Solve

4 x = \frac{π}{2} + 2 πn : x = \frac{π}{8} + \frac{πn}{2}

Solve

4 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{8} + \frac{πn}{2}

x = \frac{π}{8} + \frac{πn}{2}, x = \frac{3 π}{8} + \frac{πn}{2}

tan (2 θ) = \frac{- 1}{1}

cos^{2} (\frac{x}{2}) = \frac{1}{2}

5^{5 - 3 c s c (θ)} = 1

sin (z) = \frac{4}{7}

2 cos (θ) - 2 cos (3 θ) = 0

What is the general solution for 2cos(4x)=0 ?
The general solution for 2cos(4x)=0 is x= pi/8+(pin)/2 ,x=(3pi)/8+(pin)/2