What is the general solution for sin(a)=-1/8 ,(3pi)/2 <= a<= 2pi ?

The general solution for sin(a)=-1/8 ,(3pi)/2 <= a<= 2pi is a=-0.12532…+2pi

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sin(a)=-1/8 ,(3pi)/2 <= a<= 2pi

sin (a) = - \frac{1}{8}, \frac{3 π}{2} \leq a \leq 2 π

a = - 0.12532 \dots + 2 π

Solution steps

sin (a) = - \frac{1}{8}, \frac{3 π}{2} \leq a \leq 2 π

Apply trig inverse properties

a = arcsin (- \frac{1}{8}) + 2 πn, a = π + arcsin (\frac{1}{8}) + 2 πn

Solutions for the range

\frac{3 π}{2} \leq a \leq 2 π

a = - arcsin (\frac{1}{8}) + 2 π

Show solutions in decimal form

a = - 0.12532 \dots + 2 π

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sin (x) + cos (x) = \frac{3}{2}

cos^{2} (x) - sin^{2} (x) - 5 sin (x) = 3

sin (θ) = - \frac{21}{5}

t, cos (2 t) - sin (t) = o

What is the general solution for sin(a)=-1/8 ,(3pi)/2 <= a<= 2pi ?
The general solution for sin(a)=-1/8 ,(3pi)/2 <= a<= 2pi is a=-0.12532…+2pi