What is the general solution for 4sin(x)+1=0 ?

The general solution for 4sin(x)+1=0 is x=-0.25268…+2pin,x=pi+0.25268…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4sin(x)+1=0

4 sin (x) + 1 = 0

x = - 0.25268 \dots + 2 πn, x = π + 0.25268 \dots + 2 πn

Solution steps

4 sin (x) + 1 = 0

Move

1

to the right side

4 sin (x) = - 1

Divide both sides by

4

sin (x) = - \frac{1}{4}

Apply trig inverse properties

x = arcsin (- \frac{1}{4}) + 2 πn, x = π + arcsin (\frac{1}{4}) + 2 πn

Show solutions in decimal form

x = - 0.25268 \dots + 2 πn, x = π + 0.25268 \dots + 2 πn

cos^{2} (x) + cos^{2} (30) + cos^{2} (75) = 1

\frac{sin ( 1.3785 )}{70} = \frac{sin ( a )}{7}

cos^{2} (x) - 6 cos (x) - 7 = 0

cos (θ) = 0, 0 \leq θ \leq 2 π

- 2 sin (x) - 2 + 4 sin^{2} (x) = 0

What is the general solution for 4sin(x)+1=0 ?
The general solution for 4sin(x)+1=0 is x=-0.25268…+2pin,x=pi+0.25268…+2pin