What is the general solution for -0.6=sin(2x) ?

The general solution for -0.6=sin(2x) is x=-(0.64350…)/2+pin,x= pi/2+(0.64350…)/2+pin

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-0.6=sin(2x)

- 0.6 = sin (2 x)

x = - \frac{0.64350 \dots}{2} + πn, x = \frac{π}{2} + \frac{0.64350 \dots}{2} + πn

Solution steps

- 0.6 = sin (2 x)

Switch sides

sin (2 x) = - 0.6

Apply trig inverse properties

2 x = arcsin (- 0.6) + 2 πn, 2 x = π + arcsin (0.6) + 2 πn

Solve

2 x = arcsin (- 0.6) + 2 πn : x = - \frac{arcsin ( \frac{3}{5} )}{2} + πn

Solve

2 x = π + arcsin (0.6) + 2 πn : x = \frac{π}{2} + \frac{arcsin ( 0.6 )}{2} + πn

x = - \frac{arcsin ( \frac{3}{5} )}{2} + πn, x = \frac{π}{2} + \frac{arcsin ( 0.6 )}{2} + πn

Show solutions in decimal form

x = - \frac{0.64350 \dots}{2} + πn, x = \frac{π}{2} + \frac{0.64350 \dots}{2} + πn

x, (sin (π x) + cos (π y))^{5} = 36

sin (θ) = - \frac{2}{2}, 0 \leq θ < 2 π

2 sin (\frac{1}{2} x) + 2 = 0

\frac{cos ( x )}{sin ( x )} = - 0.05467

2 sin^{4} (x) + 2 sin^{2} (x) cos^{2} (x) = 1

What is the general solution for -0.6=sin(2x) ?
The general solution for -0.6=sin(2x) is x=-(0.64350…)/2+pin,x= pi/2+(0.64350…)/2+pin