What is the general solution for -sec^2(x)+tan(x)+1=0 ?

The general solution for -sec^2(x)+tan(x)+1=0 is x=pin,x= pi/4+pin

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-sec^2(x)+tan(x)+1=0

- sec^{2} (x) + tan (x) + 1 = 0

x = πn, x = \frac{π}{4} + πn

Solution steps

- sec^{2} (x) + tan (x) + 1 = 0

Rewrite using trig identities

tan (x) - tan^{2} (x) = 0

Solve by substitution

tan (x) = 0, tan (x) = 1

tan (x) = 0 : x = πn

tan (x) = 1 : x = \frac{π}{4} + πn

Combine all the solutions

x = πn, x = \frac{π}{4} + πn

tan (x) = - 0.8

cos^{3} (x) - 1 = 0

1.31 sin (3 5^{\circ}) = 2.42 sin (x)

cos (x + 6 0^{\circ}) = \frac{1}{2}

3 cos (θ) = - cos (θ) tan (θ)

What is the general solution for -sec^2(x)+tan(x)+1=0 ?
The general solution for -sec^2(x)+tan(x)+1=0 is x=pin,x= pi/4+pin