What is the general solution for 3cos^2(x)=1-5sin(x) ?

The general solution for 3cos^2(x)=1-5sin(x) is x=-0.33983…+2pin,x=pi+0.33983…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3cos^2(x)=1-5sin(x)

3 cos^{2} (x) = 1 - 5 sin (x)

x = - 0.33983 \dots + 2 πn, x = π + 0.33983 \dots + 2 πn

Solution steps

3 cos^{2} (x) = 1 - 5 sin (x)

Subtract

1 - 5 sin (x)

from both sides

3 cos^{2} (x) - 1 + 5 sin (x) = 0

Rewrite using trig identities

2 - 3 sin^{2} (x) + 5 sin (x) = 0

Solve by substitution

sin (x) = - \frac{1}{3}, sin (x) = 2

sin (x) = - \frac{1}{3} : x = arcsin (- \frac{1}{3}) + 2 πn, x = π + arcsin (\frac{1}{3}) + 2 πn

sin (x) = 2 :

No Solution

Combine all the solutions

x = arcsin (- \frac{1}{3}) + 2 πn, x = π + arcsin (\frac{1}{3}) + 2 πn

Show solutions in decimal form

x = - 0.33983 \dots + 2 πn, x = π + 0.33983 \dots + 2 πn

x, 2 sin (3 x) - 1 = 0

2 (cos (t)) 2 - cos (t) - 1 = 0

x, y^{(i v)} - 16 y = - 8 cosh (2 x)

cos (c) = cos (7) cos (6 0^{\circ})

cos (x π) = (- 1)^{n}

What is the general solution for 3cos^2(x)=1-5sin(x) ?
The general solution for 3cos^2(x)=1-5sin(x) is x=-0.33983…+2pin,x=pi+0.33983…+2pin