What is the general solution for 2.1sin(θ)=1.33sin(θ+90) ?

The general solution for 2.1sin(θ)=1.33sin(θ+90) is θ=0.56456…+180n

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2.1sin(θ)=1.33sin(θ+90)

2.1 sin (θ) = 1.33 sin (θ + 9 0^{\circ})

θ = 0.56456 \dots + 18 0^{\circ} n

Solution steps

2.1 sin (θ) = 1.33 sin (θ + 9 0^{\circ})

Rewrite using trig identities

2.1 sin (θ) = 1.33 cos (θ)

Subtract

1.33 cos (θ)

from both sides

2.1 sin (θ) - 1.33 cos (θ) = 0

Rewrite using trig identities

2.1 tan (θ) - 1.33 = 0

Multiply both sides by

100

210 tan (θ) - 133 = 0

Move

133

to the right side

210 tan (θ) = 133

Divide both sides by

210

tan (θ) = \frac{19}{30}

Apply trig inverse properties

θ = arctan (\frac{19}{30}) + 18 0^{\circ} n

Show solutions in decimal form

θ = 0.56456 \dots + 18 0^{\circ} n

1 sin (4 5^{\circ}) = 1.33 sin (θ)

3 cot^{2} (x) = 9

1 2^{(2)} = 1 3^{(2)} + 5^{(2)} - 2 (13) (5) cos (B)

tan (6 t) = 2

sin (2 x) - sin (x) + cos (2 x) + cos (x) = 0

What is the general solution for 2.1sin(θ)=1.33sin(θ+90) ?
The general solution for 2.1sin(θ)=1.33sin(θ+90) is θ=0.56456…+180n