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Popular Trigonometry >

8.59tan^2(θ)-24tan(θ)+15.29=0

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Solution

8.59tan2(θ)−24tan(θ)+15.29=0

Solution

θ=1.06631…+πn,θ=0.77671…+πn
+1
Degrees
θ=61.09560…∘+180∘n,θ=44.50236…∘+180∘n
Solution steps
8.59tan2(θ)−24tan(θ)+15.29=0
Solve by substitution
8.59tan2(θ)−24tan(θ)+15.29=0
Let: tan(θ)=u8.59u2−24u+15.29=0
8.59u2−24u+15.29=0:u=8591200+126589​​,u=8591200−126589​​
8.59u2−24u+15.29=0
Multiply both sides by 100
8.59u2−24u+15.29=0
To eliminate decimal points, multiply by 10 for every digit after the decimal pointThere are 2digits to the right of the decimal point, therefore multiply by 1008.59u2⋅100−24u⋅100+15.29⋅100=0⋅100
Refine859u2−2400u+1529=0
859u2−2400u+1529=0
Solve with the quadratic formula
859u2−2400u+1529=0
Quadratic Equation Formula:
For a=859,b=−2400,c=1529u1,2​=2⋅859−(−2400)±(−2400)2−4⋅859⋅1529​​
u1,2​=2⋅859−(−2400)±(−2400)2−4⋅859⋅1529​​
(−2400)2−4⋅859⋅1529​=2126589​
(−2400)2−4⋅859⋅1529​
Apply exponent rule: (−a)n=an,if n is even(−2400)2=24002=24002−4⋅859⋅1529​
Multiply the numbers: 4⋅859⋅1529=5253644=24002−5253644​
24002=5760000=5760000−5253644​
Subtract the numbers: 5760000−5253644=506356=506356​
Prime factorization of 506356:22⋅277⋅457
506356
=22⋅277⋅457​
Apply radical rule: =22​277⋅457​
Apply radical rule: 22​=2=2277⋅457​
Refine=2126589​
u1,2​=2⋅859−(−2400)±2126589​​
Separate the solutionsu1​=2⋅859−(−2400)+2126589​​,u2​=2⋅859−(−2400)−2126589​​
u=2⋅859−(−2400)+2126589​​:8591200+126589​​
2⋅859−(−2400)+2126589​​
Apply rule −(−a)=a=2⋅8592400+2126589​​
Multiply the numbers: 2⋅859=1718=17182400+2126589​​
Factor 2400+2126589​:2(1200+126589​)
2400+2126589​
Rewrite as=2⋅1200+2126589​
Factor out common term 2=2(1200+126589​)
=17182(1200+126589​)​
Cancel the common factor: 2=8591200+126589​​
u=2⋅859−(−2400)−2126589​​:8591200−126589​​
2⋅859−(−2400)−2126589​​
Apply rule −(−a)=a=2⋅8592400−2126589​​
Multiply the numbers: 2⋅859=1718=17182400−2126589​​
Factor 2400−2126589​:2(1200−126589​)
2400−2126589​
Rewrite as=2⋅1200−2126589​
Factor out common term 2=2(1200−126589​)
=17182(1200−126589​)​
Cancel the common factor: 2=8591200−126589​​
The solutions to the quadratic equation are:u=8591200+126589​​,u=8591200−126589​​
Substitute back u=tan(θ)tan(θ)=8591200+126589​​,tan(θ)=8591200−126589​​
tan(θ)=8591200+126589​​,tan(θ)=8591200−126589​​
tan(θ)=8591200+126589​​:θ=arctan(8591200+126589​​)+πn
tan(θ)=8591200+126589​​
Apply trig inverse properties
tan(θ)=8591200+126589​​
General solutions for tan(θ)=8591200+126589​​tan(x)=a⇒x=arctan(a)+πnθ=arctan(8591200+126589​​)+πn
θ=arctan(8591200+126589​​)+πn
tan(θ)=8591200−126589​​:θ=arctan(8591200−126589​​)+πn
tan(θ)=8591200−126589​​
Apply trig inverse properties
tan(θ)=8591200−126589​​
General solutions for tan(θ)=8591200−126589​​tan(x)=a⇒x=arctan(a)+πnθ=arctan(8591200−126589​​)+πn
θ=arctan(8591200−126589​​)+πn
Combine all the solutionsθ=arctan(8591200+126589​​)+πn,θ=arctan(8591200−126589​​)+πn
Show solutions in decimal formθ=1.06631…+πn,θ=0.77671…+πn

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Frequently Asked Questions (FAQ)

  • What is the general solution for 8.59tan^2(θ)-24tan(θ)+15.29=0 ?

    The general solution for 8.59tan^2(θ)-24tan(θ)+15.29=0 is θ=1.06631…+pin,θ=0.77671…+pin
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