What is the general solution for cos(2x-1)=sin(3x+6) ?

The general solution for cos(2x-1)=sin(3x+6) is x=(4pin+pi-10)/(10),x=2pin+pi-7-pi/2

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cos(2x-1)=sin(3x+6)

cos (2 x - 1) = sin (3 x + 6)

x = \frac{4 πn + π - 10}{10}, x = 2 πn + π - 7 - \frac{π}{2}

Solution steps

cos (2 x - 1) = sin (3 x + 6)

Rewrite using trig identities

cos (2 x - 1) = sin (\frac{π}{2} - (2 x - 1))

Apply trig inverse properties

3 x + 6 = \frac{π}{2} - (2 x - 1) + 2 πn, 3 x + 6 = π - (\frac{π}{2} - (2 x - 1)) + 2 πn

3 x + 6 = \frac{π}{2} - (2 x - 1) + 2 πn : x = \frac{4 πn + π - 10}{10}

3 x + 6 = π - (\frac{π}{2} - (2 x - 1)) + 2 πn : x = 2 πn + π - 7 - \frac{π}{2}

x = \frac{4 πn + π - 10}{10}, x = 2 πn + π - 7 - \frac{π}{2}

\frac{sin ( b )}{300} = \frac{sin ( 4 9 ^{\circ} )}{500}

sin (θ) = cos (2 θ + 6 0^{\circ})

tan (θ) = \frac{- 12}{5}

\frac{1 + tan ( \frac{x}{2} )}{1 - tan ( \frac{x}{2} )} = 4.137131

cos (θ) = 0.51

What is the general solution for cos(2x-1)=sin(3x+6) ?
The general solution for cos(2x-1)=sin(3x+6) is x=(4pin+pi-10)/(10),x=2pin+pi-7-pi/2