What is the general solution for 7/2 =3sin(b(pi/2))+2 ?

The general solution for 7/2 =3sin(b(pi/2))+2 is b= 1/3+4n,b= 5/3+4n

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7/2 =3sin(b(pi/2))+2

\frac{7}{2} = 3 sin (b (\frac{π}{2})) + 2

b = \frac{1}{3} + 4 n, b = \frac{5}{3} + 4 n

Solution steps

\frac{7}{2} = 3 sin (b (\frac{π}{2})) + 2

Switch sides

3 sin (b \frac{π}{2}) + 2 = \frac{7}{2}

Move

2

to the right side

3 sin (b \frac{π}{2}) = \frac{3}{2}

Divide both sides by

3

sin (b \frac{π}{2}) = \frac{1}{2}

General solutions for

sin (b \frac{π}{2}) = \frac{1}{2}

b \frac{π}{2} = \frac{π}{6} + 2 πn, b \frac{π}{2} = \frac{5 π}{6} + 2 πn

Solve

b \frac{π}{2} = \frac{π}{6} + 2 πn : b = \frac{1}{3} + 4 n

Solve

b \frac{π}{2} = \frac{5 π}{6} + 2 πn : b = \frac{5}{3} + 4 n

b = \frac{1}{3} + 4 n, b = \frac{5}{3} + 4 n

cos (x) = \frac{2}{8}

y, x = 4 sin (2 y)

cos^{2} (x) - \frac{5}{2} cos (x) - \frac{3}{2} = 0

x, sin (4 x) = \frac{1}{2}

sec (2 x - 1 0^{\circ}) = csc (5 0^{\circ})

What is the general solution for 7/2 =3sin(b(pi/2))+2 ?
The general solution for 7/2 =3sin(b(pi/2))+2 is b= 1/3+4n,b= 5/3+4n