What is the general solution for 4cos(2t)=2 ?

The general solution for 4cos(2t)=2 is t= pi/6+pin,t=(5pi)/6+pin

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4cos(2t)=2

4 cos (2 t) = 2

t = \frac{π}{6} + πn, t = \frac{5 π}{6} + πn

Solution steps

4 cos (2 t) = 2

Divide both sides by

4

cos (2 t) = \frac{1}{2}

General solutions for

cos (2 t) = \frac{1}{2}

2 t = \frac{π}{3} + 2 πn, 2 t = \frac{5 π}{3} + 2 πn

Solve

2 t = \frac{π}{3} + 2 πn : t = \frac{π}{6} + πn

Solve

2 t = \frac{5 π}{3} + 2 πn : t = \frac{5 π}{6} + πn

t = \frac{π}{6} + πn, t = \frac{5 π}{6} + πn

tan (θ) = \frac{10}{5.32}

2 cos (x) = \frac{6}{7}

tan (θ) = \frac{1}{2}, π < θ < \frac{3 π}{2}

\frac{7}{2} = 3 sin (b (\frac{π}{2})) + 2

cos (x) = \frac{2}{8}

What is the general solution for 4cos(2t)=2 ?
The general solution for 4cos(2t)=2 is t= pi/6+pin,t=(5pi)/6+pin