What is the general solution for tan(θ)= 12/5 ,0<= θ<= pi/2 ?

The general solution for tan(θ)= 12/5 ,0<= θ<= pi/2 is θ=1.17600…

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tan(θ)= 12/5 ,0<= θ<= pi/2

tan (θ) = \frac{12}{5}, 0 \leq θ \leq \frac{π}{2}

θ = 1.17600 \dots

Solution steps

tan (θ) = \frac{12}{5}, 0 \leq θ \leq \frac{π}{2}

Apply trig inverse properties

θ = arctan (\frac{12}{5}) + πn

Solutions for the range

0 \leq θ \leq \frac{π}{2}

θ = arctan (\frac{12}{5})

Show solutions in decimal form

θ = 1.17600 \dots

sin (x) = \frac{420}{2.3}

cos (x) = \frac{14}{14}

x, 5 = 4 cos (3 x) + 9

sin^{2} (x) cos (x) + sin (x) = 0

x, 8 sec (x) + 8 tan (x) = 8

What is the general solution for tan(θ)= 12/5 ,0<= θ<= pi/2 ?
The general solution for tan(θ)= 12/5 ,0<= θ<= pi/2 is θ=1.17600…