What is the general solution for sin(θ-pi/2)=cos(θ) ?

The general solution for sin(θ-pi/2)=cos(θ) is θ= pi/2+2pin,θ=(3pi)/2+2pin

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sin(θ-pi/2)=cos(θ)

sin (θ - \frac{π}{2}) = cos (θ)

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

sin (θ - \frac{π}{2}) = cos (θ)

Rewrite using trig identities

- cos (θ) = cos (θ)

Subtract

cos (θ)

from both sides

- 2 cos (θ) = 0

Divide both sides by

- 2

cos (θ) = 0

General solutions for

cos (θ) = 0

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

sec^{2} (x) - \frac{4}{3} = 0

sin (30 t) = - 0.625

sin (θ) = - \frac{2}{9}

cos (x + 3) = cos (x)

sin (x) - cos (x) = \frac{1}{3}, sin (2 x)

What is the general solution for sin(θ-pi/2)=cos(θ) ?
The general solution for sin(θ-pi/2)=cos(θ) is θ= pi/2+2pin,θ=(3pi)/2+2pin