What is the general solution for -2(sin^2(x)-cos^2(x))=0 ?

The general solution for -2(sin^2(x)-cos^2(x))=0 is x= pi/4+pin,x=(3pi)/4+pin

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-2(sin^2(x)-cos^2(x))=0

- 2 (sin^{2} (x) - cos^{2} (x)) = 0

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

- 2 (sin^{2} (x) - cos^{2} (x)) = 0

Rewrite using trig identities

- 2 (- cos (2 x)) = 0

Divide both sides by

- 2

- cos (2 x) = 0

Divide both sides by

- 1

cos (2 x) = 0

General solutions for

cos (2 x) = 0

2 x = \frac{π}{2} + 2 πn, 2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{π}{2} + 2 πn : x = \frac{π}{4} + πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

2 sin^{2} (x) - 5 sin (x) - 4 = 0

sin (θ) = 0.4815

6 cos^{2} (2 x) = sin (2 x) + 5

sin (A) = \frac{4}{5}, sin (2 A)

\frac{1}{2} (1 + cos (x)) = 0.6294095226

What is the general solution for -2(sin^2(x)-cos^2(x))=0 ?
The general solution for -2(sin^2(x)-cos^2(x))=0 is x= pi/4+pin,x=(3pi)/4+pin