What is the general solution for sin(θ)=0.4815 ?

The general solution for sin(θ)=0.4815 is θ=0.50236…+2pin,θ=pi-0.50236…+2pin

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sin(θ)=0.4815

sin (θ) = 0.4815

θ = 0.50236 \dots + 2 πn, θ = π - 0.50236 \dots + 2 πn

Solution steps

sin (θ) = 0.4815

Apply trig inverse properties

θ = arcsin (0.4815) + 2 πn, θ = π - arcsin (0.4815) + 2 πn

Show solutions in decimal form

θ = 0.50236 \dots + 2 πn, θ = π - 0.50236 \dots + 2 πn

6 cos^{2} (2 x) = sin (2 x) + 5

sin (A) = \frac{4}{5}, sin (2 A)

\frac{1}{2} (1 + cos (x)) = 0.6294095226

2 + 2 cos (x) = 6 cos (x)

120 = 120 sin (\frac{π}{3} c)

What is the general solution for sin(θ)=0.4815 ?
The general solution for sin(θ)=0.4815 is θ=0.50236…+2pin,θ=pi-0.50236…+2pin