What is the general solution for cos(x)=-7/9 , pi/2 <x<pi ?

The general solution for cos(x)=-7/9 , pi/2 <x<pi is x=2.46191…

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cos(x)=-7/9 , pi/2 <x<pi

cos (x) = - \frac{7}{9}, \frac{π}{2} < x < π

x = 2.46191 \dots

Solution steps

cos (x) = - \frac{7}{9}, \frac{π}{2} < x < π

Apply trig inverse properties

x = arccos (- \frac{7}{9}) + 2 πn, x = - arccos (- \frac{7}{9}) + 2 πn

Solutions for the range

\frac{π}{2} < x < π

x = arccos (- \frac{7}{9})

Show solutions in decimal form

x = 2.46191 \dots

y, x + arctan (\frac{y}{x}) = 0

sin (45 + 2 α) = \frac{3}{2}

θ, 2 sin (θ) - 5 = 0

(tan (x) - 3) (2 sin (x) - 1) = 0

- 2 (sin^{2} (x) - cos^{2} (x)) = 0

What is the general solution for cos(x)=-7/9 , pi/2 <x<pi ?
The general solution for cos(x)=-7/9 , pi/2 <x<pi is x=2.46191…