What is the general solution for sin(α)=cos^2(45) ?

The general solution for sin(α)=cos^2(45) is α=30+360n,α=150+360n

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sin(α)=cos^2(45)

sin (α) = cos^{2} (4 5^{\circ})

α = 3 0^{\circ} + 36 0^{\circ} n, α = 15 0^{\circ} + 36 0^{\circ} n

Solution steps

sin (α) = cos^{2} (4 5^{\circ})

cos (4 5^{\circ}) = \frac{2}{2}

sin (α) = (\frac{2}{2})^{2}

Simplify

(\frac{2}{2})^{2} : \frac{1}{2}

General solutions for

sin (α) = \frac{1}{2}

α = 3 0^{\circ} + 36 0^{\circ} n, α = 15 0^{\circ} + 36 0^{\circ} n

0 = - 2 sin^{2} (x) + cos^{2} (x)

t, 3 cos (5 t) = 2

2 sin (x) cos (x) + 3 cos (x) = 0

tan (x) = 60

t, f = cos (t_{0} t)

What is the general solution for sin(α)=cos^2(45) ?
The general solution for sin(α)=cos^2(45) is α=30+360n,α=150+360n