What is the general solution for sqrt(3-2cos(x))=2 ?

The general solution for sqrt(3-2cos(x))=2 is x=(2pi)/3+2pin,x=(4pi)/3+2pin

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sqrt(3-2cos(x))=2

3 - 2 cos (x) = 2

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

Solution steps

3 - 2 cos (x) = 2

Square both sides:

3 - 2 cos (x) = 4

3 - 2 cos (x) = 4

Solve

3 - 2 cos (x) = 4 : cos (x) = - \frac{1}{2}

cos (x) = - \frac{1}{2}

Verify Solutions:

cos (x) = - \frac{1}{2}

True

The solution is

cos (x) = - \frac{1}{2}

General solutions for

cos (x) = - \frac{1}{2}

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

tan (θ) = - \frac{8}{5}

sin (θ) - 0.1 \cdot cos (θ) = 0.56632

3 = 2 cos^{2} (x) + 3 sin (x)

- 6 cos^{2} (θ) = 0

arctan (x) = 60

What is the general solution for sqrt(3-2cos(x))=2 ?
The general solution for sqrt(3-2cos(x))=2 is x=(2pi)/3+2pin,x=(4pi)/3+2pin