What is the general solution for sec^2(θ)+sec(θ)=2,2pi<= θ<= 3pi ?

The general solution for sec^2(θ)+sec(θ)=2,2pi<= θ<= 3pi is θ=2pi,θ=(8pi)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sec^2(θ)+sec(θ)=2,2pi<= θ<= 3pi

sec^{2} (θ) + sec (θ) = 2, 2 π \leq θ \leq 3 π

θ = 2 π, θ = \frac{8 π}{3}

Solution steps

sec^{2} (θ) + sec (θ) = 2, 2 π \leq θ \leq 3 π

Solve by substitution

sec (θ) = 1, sec (θ) = - 2

sec (θ) = 1, 2 π \leq θ \leq 3 π : θ = 2 π

sec (θ) = - 2, 2 π \leq θ \leq 3 π : θ = \frac{8 π}{3}

Combine all the solutions

θ = 2 π, θ = \frac{8 π}{3}

6 sec^{2} (x) = 0

3 - 2 cos (x) = 2

tan (θ) = - \frac{8}{5}

sin (θ) - 0.1 \cdot cos (θ) = 0.56632

3 = 2 cos^{2} (x) + 3 sin (x)

What is the general solution for sec^2(θ)+sec(θ)=2,2pi<= θ<= 3pi ?
The general solution for sec^2(θ)+sec(θ)=2,2pi<= θ<= 3pi is θ=2pi,θ=(8pi)/3