What is the general solution for c^9=3tan(-3x+c) ?

The general solution for c^9=3tan(-3x+c) is x=-(arctan((c^9)/3))/(3)-(pin)/3+c/3

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c^9=3tan(-3x+c)

c^{9} = 3 tan (- 3 x + c)

x = - \frac{arctan ( \frac{c ^{9}}{3} )}{3} - \frac{πn}{3} + \frac{c}{3}

Solution steps

c^{9} = 3 tan (- 3 x + c)

Switch sides

3 tan (- 3 x + c) = c^{9}

Divide both sides by

3

tan (- 3 x + c) = \frac{c ^{9}}{3}

Apply trig inverse properties

- 3 x + c = arctan (\frac{c ^{9}}{3}) + πn

Solve

- 3 x + c = arctan (\frac{c ^{9}}{3}) + πn : x = - \frac{arctan ( \frac{c ^{9}}{3} )}{3} - \frac{πn}{3} + \frac{c}{3}

x = - \frac{arctan ( \frac{c ^{9}}{3} )}{3} - \frac{πn}{3} + \frac{c}{3}

1 = 8 + 7 sin (15 t)

4 sin (θ) = 4 - 4 sin (θ)

tan (θ) = (- 3)

sin^{2} (x) + cos (x) + 1 = 0, 0 \leq x \leq 2 π

sin (2 x) = \frac{- 1}{3}

What is the general solution for c^9=3tan(-3x+c) ?
The general solution for c^9=3tan(-3x+c) is x=-(arctan((c^9)/3))/(3)-(pin)/3+c/3