zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

c^9=3tan(-3x+c)

解答

c^{9} = 3 tan (- 3 x + c)

解答

x = - \frac{arctan ( \frac{c ^{9}}{3} )}{3} - \frac{πn}{3} + \frac{c}{3}

求解步骤

c^{9} = 3 tan (- 3 x + c)

交换两边

3 tan (- 3 x + c) = c^{9}

两边除以

3

3 tan (- 3 x + c) = c^{9}

两边除以

3

\frac{3 tan ( - 3 x + c )}{3} = \frac{c ^{9}}{3}

化简

tan (- 3 x + c) = \frac{c ^{9}}{3}

tan (- 3 x + c) = \frac{c ^{9}}{3}

使用反三角函数性质

tan (- 3 x + c) = \frac{c ^{9}}{3}

tan (- 3 x + c) = \frac{c ^{9}}{3}

的通解

tan (x) = a \Rightarrow x = arctan (a) + πn

- 3 x + c = arctan (\frac{c ^{9}}{3}) + πn

- 3 x + c = arctan (\frac{c ^{9}}{3}) + πn

解

- 3 x + c = arctan (\frac{c ^{9}}{3}) + πn : x = - \frac{arctan ( \frac{c ^{9}}{3} )}{3} - \frac{πn}{3} + \frac{c}{3}

- 3 x + c = arctan (\frac{c ^{9}}{3}) + πn

将

c

到右边

- 3 x + c = arctan (\frac{c ^{9}}{3}) + πn

两边减去

c

- 3 x + c - c = arctan (\frac{c ^{9}}{3}) + πn - c

化简

- 3 x = arctan (\frac{c ^{9}}{3}) + πn - c

- 3 x = arctan (\frac{c ^{9}}{3}) + πn - c

两边除以

- 3

- 3 x = arctan (\frac{c ^{9}}{3}) + πn - c

两边除以

- 3

\frac{- 3 x}{- 3} = \frac{arctan ( \frac{c ^{9}}{3} )}{- 3} + \frac{πn}{- 3} - \frac{c}{- 3}

化简

\frac{- 3 x}{- 3} = \frac{arctan ( \frac{c ^{9}}{3} )}{- 3} + \frac{πn}{- 3} - \frac{c}{- 3}

化简

\frac{- 3 x}{- 3} : x

\frac{- 3 x}{- 3}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{3 x}{3}

数字相除:

\frac{3}{3} = 1

= x

化简

\frac{arctan ( \frac{c ^{9}}{3} )}{- 3} + \frac{πn}{- 3} - \frac{c}{- 3} : - \frac{arctan ( \frac{c ^{9}}{3} )}{3} - \frac{πn}{3} + \frac{c}{3}

\frac{arctan ( \frac{c ^{9}}{3} )}{- 3} + \frac{πn}{- 3} - \frac{c}{- 3}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{arctan ( \frac{c ^{9}}{3} )}{3} + \frac{πn}{- 3} - \frac{c}{- 3}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{arctan ( \frac{c ^{9}}{3} )}{3} - \frac{πn}{3} - \frac{c}{- 3}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{arctan ( \frac{c ^{9}}{3} )}{3} - \frac{πn}{3} - (- \frac{c}{3})

使用法则

- (- a) = a

= - \frac{arctan ( \frac{c ^{9}}{3} )}{3} - \frac{πn}{3} + \frac{c}{3}

x = - \frac{arctan ( \frac{c ^{9}}{3} )}{3} - \frac{πn}{3} + \frac{c}{3}

x = - \frac{arctan ( \frac{c ^{9}}{3} )}{3} - \frac{πn}{3} + \frac{c}{3}

x = - \frac{arctan ( \frac{c ^{9}}{3} )}{3} - \frac{πn}{3} + \frac{c}{3}

x = - \frac{arctan ( \frac{c ^{9}}{3} )}{3} - \frac{πn}{3} + \frac{c}{3}

作图

流行的例子

1 = 8 + 7 sin (15 t)

4sin(θ)=4-4sin(θ)

4 sin (θ) = 4 - 4 sin (θ)

tan(θ)=(-sqrt(3))

tan (θ) = (- 3)

sin^2(x)+cos(x)+1=0,0<= x<= 2pi

sin^{2} (x) + cos (x) + 1 = 0, 0 \leq x \leq 2 π

sin(2x)=(-1)/(sqrt(3))

sin (2 x) = \frac{- 1}{3}