What is the general solution for 1=8+7sin(15t) ?

The general solution for 1=8+7sin(15t) is t= pi/(10)+(2pin)/(15)

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1=8+7sin(15t)

1 = 8 + 7 sin (15 t)

t = \frac{π}{10} + \frac{2 πn}{15}

Solution steps

1 = 8 + 7 sin (15 t)

Switch sides

8 + 7 sin (15 t) = 1

Move

8

to the right side

7 sin (15 t) = - 7

Divide both sides by

7

sin (15 t) = - 1

General solutions for

sin (15 t) = - 1

15 t = \frac{3 π}{2} + 2 πn

Solve

15 t = \frac{3 π}{2} + 2 πn : t = \frac{π}{10} + \frac{2 πn}{15}

t = \frac{π}{10} + \frac{2 πn}{15}

4 sin (θ) = 4 - 4 sin (θ)

tan (θ) = (- 3)

sin^{2} (x) + cos (x) + 1 = 0, 0 \leq x \leq 2 π

sin (2 x) = \frac{- 1}{3}

cos (2 θ) = 1 + 3 sin (θ)

What is the general solution for 1=8+7sin(15t) ?
The general solution for 1=8+7sin(15t) is t= pi/(10)+(2pin)/(15)