What is the general solution for solvefor θ,1=sin(θ) ?

The general solution for solvefor θ,1=sin(θ) is θ= pi/2+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor θ,1=sin(θ)

solve for

θ, 1 = sin (θ)

θ = \frac{π}{2} + 2 πn

Solution steps

1 = sin (θ)

Switch sides

sin (θ) = 1

General solutions for

sin (θ) = 1

θ = \frac{π}{2} + 2 πn

tan (2 x) = 2

\frac{sin ( b )}{13.1} = \frac{sin ( 112. 1 ^{\circ} )}{24.1}

tan (α) = \frac{0.006}{π \cdot 0.027}

sec^{2} (θ) tan (θ) = 2 tan (θ)

tan^{5} (x) + tan^{3} (x) = 0

What is the general solution for solvefor θ,1=sin(θ) ?
The general solution for solvefor θ,1=sin(θ) is θ= pi/2+2pin