What is the general solution for 4cot(x)+1=1+2cot(x) ?

The general solution for 4cot(x)+1=1+2cot(x) is x= pi/2+pin

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4cot(x)+1=1+2cot(x)

4 cot (x) + 1 = 1 + 2 cot (x)

x = \frac{π}{2} + πn

Solution steps

4 cot (x) + 1 = 1 + 2 cot (x)

Solve by substitution

cot (x) = 0

cot (x) = 0 : x = \frac{π}{2} + πn

Combine all the solutions

x = \frac{π}{2} + πn

\frac{2}{3} = sin (θ) - 0.28 cos (θ)

2 sin (x) = 3 - cos (x), 0 \leq x \leq 2 π

cos^{2} (x) = - \frac{1}{3}

4 + 4 cos (θ) = 8 cos (θ)

tan (θ) = 6, cos (θ)

What is the general solution for 4cot(x)+1=1+2cot(x) ?
The general solution for 4cot(x)+1=1+2cot(x) is x= pi/2+pin