What is the general solution for 0=-(9pi^2)/(3200)cos((pix)/(80)) ?

The general solution for 0=-(9pi^2)/(3200)cos((pix)/(80)) is x=40+160n,x=120+160n

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0=-(9pi^2)/(3200)cos((pix)/(80))

0 = - \frac{9 π ^{2}}{3200} cos (\frac{π x}{80})

x = 40 + 160 n, x = 120 + 160 n

Solution steps

0 = - \frac{9 π ^{2}}{3200} cos (\frac{π x}{80})

Switch sides

- \frac{9 π ^{2}}{3200} cos (\frac{π x}{80}) = 0

Multiply both sides by

3200

- 9 π^{2} cos (\frac{π x}{80}) = 0

Divide both sides by

- 9 π^{2}

cos (\frac{π x}{80}) = 0

General solutions for

cos (\frac{π x}{80}) = 0

\frac{π x}{80} = \frac{π}{2} + 2 πn, \frac{π x}{80} = \frac{3 π}{2} + 2 πn

Solve

\frac{π x}{80} = \frac{π}{2} + 2 πn : x = 40 + 160 n

Solve

\frac{π x}{80} = \frac{3 π}{2} + 2 πn : x = 120 + 160 n

x = 40 + 160 n, x = 120 + 160 n

cos^{2} (a) + 2 sin (a) + 1 = 0

tan (x) = \frac{5}{15}

2 sin (x + \frac{π}{9}) = - 1

1 + cos (a) = \frac{3 + 4 cos ( a )}{2}

3 cos (x) - 2 cos^{2} (x) = 0, 0^{\circ} < x < 36 0^{\circ}

What is the general solution for 0=-(9pi^2)/(3200)cos((pix)/(80)) ?
The general solution for 0=-(9pi^2)/(3200)cos((pix)/(80)) is x=40+160n,x=120+160n