What is the general solution for 2cos^2(θ)-3cos(θ)=0,(3pi)/2 <θ<2pi ?

The general solution for 2cos^2(θ)-3cos(θ)=0,(3pi)/2 <θ<2pi is No Solution for θ\in\mathbb{R}

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2cos^2(θ)-3cos(θ)=0,(3pi)/2 <θ<2pi

2 cos^{2} (θ) - 3 cos (θ) = 0, \frac{3 π}{2} < θ < 2 π

No Solution for θ \in R

Solution steps

2 cos^{2} (θ) - 3 cos (θ) = 0, \frac{3 π}{2} < θ < 2 π

Solve by substitution

cos (θ) = \frac{3}{2}, cos (θ) = 0

cos (θ) = \frac{3}{2}, \frac{3 π}{2} < θ < 2 π :

No Solution

cos (θ) = 0, \frac{3 π}{2} < θ < 2 π :

No Solution

Combine all the solutions

No Solution for θ \in R

cos (θ) = \frac{9}{17}

- 1 = \frac{tan ( x ) - ( \frac{3}{4} )}{1 + tan ( x ) ( \frac{3}{4} )}

cos (x) = - \frac{15}{13}

arctan (\frac{20}{x}) - arctan (\frac{400}{x}) = - 9.72

cos (θ) = \frac{9}{15}

What is the general solution for 2cos^2(θ)-3cos(θ)=0,(3pi)/2 <θ<2pi ?
The general solution for 2cos^2(θ)-3cos(θ)=0,(3pi)/2 <θ<2pi is No Solution for θ\in\mathbb{R}