What is the general solution for 3sin(t)=1+sin(t) ?

The general solution for 3sin(t)=1+sin(t) is t= pi/6+2pin,t=(5pi)/6+2pin

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3sin(t)=1+sin(t)

3 sin (t) = 1 + sin (t)

t = \frac{π}{6} + 2 πn, t = \frac{5 π}{6} + 2 πn

Solution steps

3 sin (t) = 1 + sin (t)

Solve by substitution

sin (t) = \frac{1}{2}

sin (t) = \frac{1}{2} : t = \frac{π}{6} + 2 πn, t = \frac{5 π}{6} + 2 πn

Combine all the solutions

t = \frac{π}{6} + 2 πn, t = \frac{5 π}{6} + 2 πn

sin^{2} (t) sin (t) = 0

cos (x) = \frac{100}{130}

sec^{2} (θ) - 1 = 0, 0 \leq θ \leq 2 π

2 cos^{2} (θ) - 3 cos (θ) = 0, \frac{3 π}{2} < θ < 2 π

cos (θ) = \frac{9}{17}

What is the general solution for 3sin(t)=1+sin(t) ?
The general solution for 3sin(t)=1+sin(t) is t= pi/6+2pin,t=(5pi)/6+2pin