What is the general solution for sin(t)=(250)/(sqrt(250^2+300^2)) ?

The general solution for sin(t)=(250)/(sqrt(250^2+300^2)) is t=0.69473…+2pin,t=pi-0.69473…+2pin

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sin(t)=(250)/(sqrt(250^2+300^2))

sin (t) = \frac{250}{25 0 ^{2} + 30 0 ^{2}}

t = 0.69473 \dots + 2 πn, t = π - 0.69473 \dots + 2 πn

Solution steps

sin (t) = \frac{250}{25 0 ^{2} + 30 0 ^{2}}

Simplify

\frac{250}{25 0 ^{2} + 30 0 ^{2}} : \frac{5 61}{61}

Apply trig inverse properties

t = arcsin (\frac{5 61}{61}) + 2 πn, t = π - arcsin (\frac{5 61}{61}) + 2 πn

Show solutions in decimal form

t = 0.69473 \dots + 2 πn, t = π - 0.69473 \dots + 2 πn

0 = sin (13 x)

cos (a) = \frac{9}{41}

sin^{2} (θ) - 2 = cos^{2} (θ)

cos (x) = 0, 88

21 = 24 + 8 cos (\frac{π t}{6})

What is the general solution for sin(t)=(250)/(sqrt(250^2+300^2)) ?
The general solution for sin(t)=(250)/(sqrt(250^2+300^2)) is t=0.69473…+2pin,t=pi-0.69473…+2pin