What is the general solution for 4cos(θ)=2cos(θ) ?

The general solution for 4cos(θ)=2cos(θ) is θ= pi/2+2pin,θ=(3pi)/2+2pin

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4cos(θ)=2cos(θ)

4 cos (θ) = 2 cos (θ)

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

4 cos (θ) = 2 cos (θ)

Solve by substitution

cos (θ) = 0

cos (θ) = 0 : θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Combine all the solutions

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

2 cos (θ) = - 2

x, cos (2 x) + \frac{2}{cos ( 2 x )} + 3 = 0

sin (t) = \frac{250}{25 0 ^{2} + 30 0 ^{2}}

0 = sin (13 x)

cos (a) = \frac{9}{41}

What is the general solution for 4cos(θ)=2cos(θ) ?
The general solution for 4cos(θ)=2cos(θ) is θ= pi/2+2pin,θ=(3pi)/2+2pin