What is the general solution for sin^2(x)+cos^2(x)=cos(2x) ?

The general solution for sin^2(x)+cos^2(x)=cos(2x) is x=pin

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sin^2(x)+cos^2(x)=cos(2x)

sin^{2} (x) + cos^{2} (x) = cos (2 x)

x = πn

Solution steps

sin^{2} (x) + cos^{2} (x) = cos (2 x)

Rewrite using trig identities

1 = cos (2 x)

Switch sides

cos (2 x) = 1

General solutions for

cos (2 x) = 1

2 x = 0 + 2 πn

Solve

2 x = 0 + 2 πn : x = πn

x = πn

(218) sin^{2} (x) + (126) sin (x) - 88 = 0

3 sin (3 x) = 0

cos (θ) csc (θ) = sin (θ) sec (θ)

64 cos^{2} (θ) = 49, (0^{\circ} \leq, θ \leq 36 0^{\circ})

y, x = 4 sec (y)

What is the general solution for sin^2(x)+cos^2(x)=cos(2x) ?
The general solution for sin^2(x)+cos^2(x)=cos(2x) is x=pin