What is the general solution for sec^2(2x)-1=0 ?

The general solution for sec^2(2x)-1=0 is x=pin,x= pi/2+pin

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sec^2(2x)-1=0

sec^{2} (2 x) - 1 = 0

x = πn, x = \frac{π}{2} + πn

Solution steps

sec^{2} (2 x) - 1 = 0

Solve by substitution

sec (2 x) = 1, sec (2 x) = - 1

sec (2 x) = 1 : x = πn

sec (2 x) = - 1 : x = \frac{π}{2} + πn

Combine all the solutions

x = πn, x = \frac{π}{2} + πn

1 = 2 cos (x)

x, y = arcsin (\frac{x}{11})

\frac{sin ( 4 8 ^{\circ} )}{13} = \frac{sin ( b )}{16}

9 cos (2 θ) = 0

8 cos (θ) + 7 = - 6 cos (θ) + 5

What is the general solution for sec^2(2x)-1=0 ?
The general solution for sec^2(2x)-1=0 is x=pin,x= pi/2+pin