What is the general solution for (sin(x))(tan(x)+1)(cos(x)+1)=0 ?

The general solution for (sin(x))(tan(x)+1)(cos(x)+1)=0 is x=2pin,x=pi+2pin,x=(3pi)/4+pin

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(sin(x))(tan(x)+1)(cos(x)+1)=0

(sin (x)) (tan (x) + 1) (cos (x) + 1) = 0

x = 2 πn, x = π + 2 πn, x = \frac{3 π}{4} + πn

Solution steps

(sin (x)) (tan (x) + 1) (cos (x) + 1) = 0

Solving each part separately

sin (x) = 0 or tan (x) + 1 = 0 or cos (x) + 1 = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

tan (x) + 1 = 0 : x = \frac{3 π}{4} + πn

cos (x) + 1 = 0 : x = π + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn, x = \frac{3 π}{4} + πn

tan (3.87 x) = - 0.78

sin (2 x) = \frac{( 2 m - 4 )}{5}

34 sin (\frac{π}{6} (x - 43)) = 34

3 sin (3 x) = 2

2 sinh (2 x) - 6 cosh (x) = 0

What is the general solution for (sin(x))(tan(x)+1)(cos(x)+1)=0 ?
The general solution for (sin(x))(tan(x)+1)(cos(x)+1)=0 is x=2pin,x=pi+2pin,x=(3pi)/4+pin