What is the general solution for 7tan(θ)+9=0 ?

The general solution for 7tan(θ)+9=0 is θ=-0.90975…+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

7tan(θ)+9=0

7 tan (θ) + 9 = 0

θ = - 0.90975 \dots + πn

Degrees

θ = - 52.12501 \dots^{\circ} + 18 0^{\circ} n

Solution steps

7 tan (θ) + 9 = 0

Move

9

to the right side

7 tan (θ) + 9 = 0

Subtract

9

from both sides

7 tan (θ) + 9 - 9 = 0 - 9

Simplify

7 tan (θ) = - 9

7 tan (θ) = - 9

Divide both sides by

7

7 tan (θ) = - 9

Divide both sides by

7

\frac{7 tan ( θ )}{7} = \frac{- 9}{7}

Simplify

tan (θ) = - \frac{9}{7}

tan (θ) = - \frac{9}{7}

Apply trig inverse properties

tan (θ) = - \frac{9}{7}

General solutions for

tan (θ) = - \frac{9}{7}

tan (x) = - a \Rightarrow x = arctan (- a) + πn

θ = arctan (- \frac{9}{7}) + πn

θ = arctan (- \frac{9}{7}) + πn

Show solutions in decimal form

θ = - 0.90975 \dots + πn

What is the general solution for 7tan(θ)+9=0 ?
The general solution for 7tan(θ)+9=0 is θ=-0.90975…+pin