What is the general solution for tan(φ)=-1/(sqrt(3)) ?

The general solution for tan(φ)=-1/(sqrt(3)) is φ=(5pi)/6+pin

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tan(φ)=-1/(sqrt(3))

tan (φ) = - \frac{1}{3}

φ = \frac{5 π}{6} + πn

Solution steps

tan (φ) = - \frac{1}{3}

Simplify

- \frac{1}{3} : - \frac{3}{3}

General solutions for

tan (φ) = - \frac{3}{3}

φ = \frac{5 π}{6} + πn

sin (3 m) = 0

cos (a) = - \frac{8}{17}, sin (b) = \frac{3}{5}

7 tan (θ) + 9 = 0

14 = - 3.75 cos (\frac{π}{6} x) + 11.25

x, f = sin (π \cdot ⌊ x ⌋)

What is the general solution for tan(φ)=-1/(sqrt(3)) ?
The general solution for tan(φ)=-1/(sqrt(3)) is φ=(5pi)/6+pin