What is the general solution for -4sin(c)-2=sin(c)+1 ?

The general solution for -4sin(c)-2=sin(c)+1 is c=-0.64350…+2pin,c=pi+0.64350…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-4sin(c)-2=sin(c)+1

- 4 sin (c) - 2 = sin (c) + 1

c = - 0.64350 \dots + 2 πn, c = π + 0.64350 \dots + 2 πn

Solution steps

- 4 sin (c) - 2 = sin (c) + 1

Solve by substitution

sin (c) = - \frac{3}{5}

sin (c) = - \frac{3}{5} : c = arcsin (- \frac{3}{5}) + 2 πn, c = π + arcsin (\frac{3}{5}) + 2 πn

Combine all the solutions

c = arcsin (- \frac{3}{5}) + 2 πn, c = π + arcsin (\frac{3}{5}) + 2 πn

Show solutions in decimal form

c = - 0.64350 \dots + 2 πn, c = π + 0.64350 \dots + 2 πn

cot^{2} (x) + 1 = 2

sin (x) = \frac{1}{3}, sec (y) = \frac{25}{24 , cos ( x + y )}

2 = 2 - π cos (t)

a, 45 = arctanh (\frac{a}{b})

x, sec (x) = 3

What is the general solution for -4sin(c)-2=sin(c)+1 ?
The general solution for -4sin(c)-2=sin(c)+1 is c=-0.64350…+2pin,c=pi+0.64350…+2pin