What is the general solution for 2cos(x)+2sin(x)=0 ?

The general solution for 2cos(x)+2sin(x)=0 is x=(3pi)/4+pin

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2cos(x)+2sin(x)=0

2 cos (x) + 2 sin (x) = 0

x = \frac{3 π}{4} + πn

Solution steps

2 cos (x) + 2 sin (x) = 0

Rewrite using trig identities

2 + 2 tan (x) = 0

Move

2

to the right side

2 tan (x) = - 2

Divide both sides by

2

tan (x) = - 1

General solutions for

tan (x) = - 1

x = \frac{3 π}{4} + πn

\frac{3}{2} = sin (arcsin (0) + c_{1})

tan^{2} (x) - sin^{2} (x) = tan^{2} (x) + sin^{2} (x)

3 cos (2 x) + cos (x) = 0

sin (2 v) = sin (1 6^{\circ})

tan (2 x) = \frac{130}{- 270 - 120}

What is the general solution for 2cos(x)+2sin(x)=0 ?
The general solution for 2cos(x)+2sin(x)=0 is x=(3pi)/4+pin