What is the general solution for 4sin^2(x)=3,0<= x<= 108 ?

The general solution for 4sin^2(x)=3,0<= x<= 108 is x=60

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4sin^2(x)=3,0<= x<= 108

4 sin^{2} (x) = 3, 0 \leq x \leq 10 8^{\circ}

x = 6 0^{\circ}

Solution steps

4 sin^{2} (x) = 3, 0 \leq x \leq 10 8^{\circ}

Solve by substitution

sin (x) = \frac{3}{2}, sin (x) = - \frac{3}{2}

sin (x) = \frac{3}{2}, 0 \leq x \leq 10 8^{\circ} : x = 6 0^{\circ}

sin (x) = - \frac{3}{2}, 0 \leq x \leq 10 8^{\circ} :

No Solution

Combine all the solutions

x = 6 0^{\circ}

3 sin (x) + 3 cos (x) = 0

4 sin (2 x) + 4 cos (x) = 0

2 + cos (2 x) + 3 cos (x) = 0

2 cos (x) = tan (x) + sec (x)

sin^{2} (x) cos (x) = \frac{2}{3 π}

What is the general solution for 4sin^2(x)=3,0<= x<= 108 ?
The general solution for 4sin^2(x)=3,0<= x<= 108 is x=60