What is the general solution for solvefor y,arctan(y)=(x^3)/3-2x+c ?

The general solution for solvefor y,arctan(y)=(x^3)/3-2x+c is y=tan((x^3)/3-2x+c)

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solvefor y,arctan(y)=(x^3)/3-2x+c

solve for

y, arctan (y) = \frac{x ^{3}}{3} - 2 x + c

y = tan (\frac{x ^{3}}{3} - 2 x + c)

Solution steps

arctan (y) = \frac{x ^{3}}{3} - 2 x + c

Apply trig inverse properties

y = tan (\frac{x ^{3}}{3} - 2 x + c)

cos (A) = \frac{3}{4}

3 cos (x) = 2 cot (x)

5 cos (7 θ) = 0

- 8 tan (y) = 0

2 cos^{2} (θ) + cos (θ) = 0, 0 \leq θ < 2 π

What is the general solution for solvefor y,arctan(y)=(x^3)/3-2x+c ?
The general solution for solvefor y,arctan(y)=(x^3)/3-2x+c is y=tan((x^3)/3-2x+c)