What is the general solution for 5cos(7θ)=0 ?

The general solution for 5cos(7θ)=0 is θ= pi/(14)+(2pin)/7 ,θ=(3pi}{14}+\frac{2pin)/7

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5cos(7θ)=0

5 cos (7 θ) = 0

θ = \frac{π}{14} + \frac{2 πn}{7}, θ = \frac{3 π}{14} + \frac{2 πn}{7}

Solution steps

5 cos (7 θ) = 0

Divide both sides by

5

cos (7 θ) = 0

General solutions for

cos (7 θ) = 0

7 θ = \frac{π}{2} + 2 πn, 7 θ = \frac{3 π}{2} + 2 πn

Solve

7 θ = \frac{π}{2} + 2 πn : θ = \frac{π}{14} + \frac{2 πn}{7}

Solve

7 θ = \frac{3 π}{2} + 2 πn : θ = \frac{3 π}{14} + \frac{2 πn}{7}

θ = \frac{π}{14} + \frac{2 πn}{7}, θ = \frac{3 π}{14} + \frac{2 πn}{7}

- 8 tan (y) = 0

2 cos^{2} (θ) + cos (θ) = 0, 0 \leq θ < 2 π

3 cos (2 x) + sin (2 x) = 0

cos (\frac{- π}{2} + \frac{x}{2}) = 0

cos (x) = - 0.175

What is the general solution for 5cos(7θ)=0 ?
The general solution for 5cos(7θ)=0 is θ= pi/(14)+(2pin)/7 ,θ=(3pi}{14}+\frac{2pin)/7