What is the general solution for (1-tanh(x))/(1+tanh(x))=2 ?

The general solution for (1-tanh(x))/(1+tanh(x))=2 is x=-1/2 ln(2)

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(1-tanh(x))/(1+tanh(x))=2

\frac{1 - tanh ( x )}{1 + tanh ( x )} = 2

x = - \frac{1}{2} ln (2)

Solution steps

\frac{1 - tanh ( x )}{1 + tanh ( x )} = 2

Rewrite using trig identities

\frac{1 - \frac{e ^{x} - e ^{- x}}{e ^{x} + e ^{- x}}}{1 + \frac{e ^{x} - e ^{- x}}{e ^{x} + e ^{- x}}} = 2

\frac{1 - \frac{e ^{x} - e ^{- x}}{e ^{x} + e ^{- x}}}{1 + \frac{e ^{x} - e ^{- x}}{e ^{x} + e ^{- x}}} = 2 : x = - \frac{1}{2} ln (2)

x = - \frac{1}{2} ln (2)

40 = tan (ln (18 + 1) + C)

tan (a) = - 26

- 5 cos (x) = 2 sin^{2} (x) + 4

5 sin (θ + 0.4636) = 1

0 = \frac{20}{3} sin (10 t) + 5 cos (10 t)

What is the general solution for (1-tanh(x))/(1+tanh(x))=2 ?
The general solution for (1-tanh(x))/(1+tanh(x))=2 is x=-1/2 ln(2)