What is the general solution for 4sin(3θ)=2 ?

The general solution for 4sin(3θ)=2 is θ= pi/(18)+(2pin)/3 ,θ=(5pi}{18}+\frac{2pin)/3

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4sin(3θ)=2

4 sin (3 θ) = 2

θ = \frac{π}{18} + \frac{2 πn}{3}, θ = \frac{5 π}{18} + \frac{2 πn}{3}

Solution steps

4 sin (3 θ) = 2

Divide both sides by

4

sin (3 θ) = \frac{1}{2}

General solutions for

sin (3 θ) = \frac{1}{2}

3 θ = \frac{π}{6} + 2 πn, 3 θ = \frac{5 π}{6} + 2 πn

Solve

3 θ = \frac{π}{6} + 2 πn : θ = \frac{π}{18} + \frac{2 πn}{3}

Solve

3 θ = \frac{5 π}{6} + 2 πn : θ = \frac{5 π}{18} + \frac{2 πn}{3}

θ = \frac{π}{18} + \frac{2 πn}{3}, θ = \frac{5 π}{18} + \frac{2 πn}{3}

cos (x) = cos (3 x) + 2 sin (2 x)

csc (x) (2 sin (x) - 2) = 0

\frac{700}{sin ( 9 0 ^{\circ} )} = \frac{236.3277}{sin ( θ )}

cos (x) + cos (2 x) = - 0.75

x, 2 y = sin (2 x)

What is the general solution for 4sin(3θ)=2 ?
The general solution for 4sin(3θ)=2 is θ= pi/(18)+(2pin)/3 ,θ=(5pi}{18}+\frac{2pin)/3