What is the general solution for sin(4x+pi/4)=1 ?

The general solution for sin(4x+pi/4)=1 is x=(pin)/2+pi/(16)

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sin(4x+pi/4)=1

sin (4 x + \frac{π}{4}) = 1

x = \frac{πn}{2} + \frac{π}{16}

Solution steps

sin (4 x + \frac{π}{4}) = 1

General solutions for

sin (4 x + \frac{π}{4}) = 1

4 x + \frac{π}{4} = \frac{π}{2} + 2 πn

Solve

4 x + \frac{π}{4} = \frac{π}{2} + 2 πn : x = \frac{πn}{2} + \frac{π}{16}

x = \frac{πn}{2} + \frac{π}{16}

cos^{2} (x) - cos (x) = 0, (0, 2 π)

csc (4 2^{\circ}) = sec (x)

x, 0 = cos (x) + 1 + sin (x)

5 sin (\frac{π}{4} x) = 4

1 - sec^{2} (θ) = tan^{2} (θ)

What is the general solution for sin(4x+pi/4)=1 ?
The general solution for sin(4x+pi/4)=1 is x=(pin)/2+pi/(16)