What is the general solution for cos^2(x)-cos(x)=0,(0,2pi) ?

The general solution for cos^2(x)-cos(x)=0,(0,2pi) is x= pi/2 ,x=(3pi)/2

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cos^2(x)-cos(x)=0,(0,2pi)

cos^{2} (x) - cos (x) = 0, (0, 2 π)

x = \frac{π}{2}, x = \frac{3 π}{2}

Solution steps

cos^{2} (x) - cos (x) = 0, (0, 2 π)

Solve by substitution

cos (x) = 1, cos (x) = 0

cos (x) = 1, (0, 2 π) :

No Solution

cos (x) = 0, (0, 2 π) : x = \frac{π}{2}, x = \frac{3 π}{2}

Combine all the solutions

x = \frac{π}{2}, x = \frac{3 π}{2}

csc (4 2^{\circ}) = sec (x)

x, 0 = cos (x) + 1 + sin (x)

5 sin (\frac{π}{4} x) = 4

1 - sec^{2} (θ) = tan^{2} (θ)

6 tan^{2} (x) = 5 sec (x)

What is the general solution for cos^2(x)-cos(x)=0,(0,2pi) ?
The general solution for cos^2(x)-cos(x)=0,(0,2pi) is x= pi/2 ,x=(3pi)/2