What is the general solution for cos^{(2)}(x)+sin(x)=1 ?

The general solution for cos^{(2)}(x)+sin(x)=1 is x=2pin,x=pi+2pin,x= pi/2+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos^{(2)}(x)+sin(x)=1

cos^{(2)} (x) + sin (x) = 1

x = 2 πn, x = π + 2 πn, x = \frac{π}{2} + 2 πn

Solution steps

cos^{(2)} (x) + sin (x) = 1

Subtract

1

from both sides

cos^{2} (x) + sin (x) - 1 = 0

Rewrite using trig identities

sin (x) - sin^{2} (x) = 0

Solve by substitution

sin (x) = 0, sin (x) = 1

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = 1 : x = \frac{π}{2} + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn, x = \frac{π}{2} + 2 πn

sin (2 q) = 0

tan (x) = \frac{218}{75}

cos (x) - 2 + 2 = 1

- 3 + cos (2 x) 2 = 0

cos (θ) cos (3 θ) - 1 = 0

What is the general solution for cos^{(2)}(x)+sin(x)=1 ?
The general solution for cos^{(2)}(x)+sin(x)=1 is x=2pin,x=pi+2pin,x= pi/2+2pin