What is the general solution for 2-sin^2(θ)+2sin(θ)=0 ?

The general solution for 2-sin^2(θ)+2sin(θ)=0 is θ=-0.82132…+2pin,θ=pi+0.82132…+2pin

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2-sin^2(θ)+2sin(θ)=0

2 - sin^{2} (θ) + 2 sin (θ) = 0

θ = - 0.82132 \dots + 2 πn, θ = π + 0.82132 \dots + 2 πn

Solution steps

2 - sin^{2} (θ) + 2 sin (θ) = 0

Solve by substitution

sin (θ) = 1 - 3, sin (θ) = 1 + 3

sin (θ) = 1 - 3 : θ = arcsin (1 - 3) + 2 πn, θ = π + arcsin (- 1 + 3) + 2 πn

sin (θ) = 1 + 3 :

No Solution

Combine all the solutions

θ = arcsin (1 - 3) + 2 πn, θ = π + arcsin (- 1 + 3) + 2 πn

Show solutions in decimal form

θ = - 0.82132 \dots + 2 πn, θ = π + 0.82132 \dots + 2 πn

tan (θ) = \frac{37.3}{36.46}

sin (θ) cos (θ) = csc (θ) sec (θ)

a, x = cos (a)

sin (\frac{1}{2} \cdot k \cdot r (1 + \frac{a ^{2}}{r ^{2}}) - 1) = π

3 sin (x) = 2 sec (x) tan (x)

What is the general solution for 2-sin^2(θ)+2sin(θ)=0 ?
The general solution for 2-sin^2(θ)+2sin(θ)=0 is θ=-0.82132…+2pin,θ=pi+0.82132…+2pin