What is the general solution for 1+2sin(x)-cos^2(x)=0 ?

The general solution for 1+2sin(x)-cos^2(x)=0 is x=2pin,x=pi+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1+2sin(x)-cos^2(x)=0

1 + 2 sin (x) - cos^{2} (x) = 0

x = 2 πn, x = π + 2 πn

Solution steps

1 + 2 sin (x) - cos^{2} (x) = 0

Rewrite using trig identities

sin^{2} (x) + 2 sin (x) = 0

Solve by substitution

sin (x) = 0, sin (x) = - 2

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = - 2 :

No Solution

Combine all the solutions

x = 2 πn, x = π + 2 πn

tan (θ) = - 3, sin (θ) < 0

x, sec (x) + 2 = 0

cos (2 x) = 0.92

cos (4 x) + 1 = 3 sin (2 x), - \frac{π}{2} \leq x \leq \frac{π}{2}

3 - 6 cos (x + \frac{π}{3}) = 0

What is the general solution for 1+2sin(x)-cos^2(x)=0 ?
The general solution for 1+2sin(x)-cos^2(x)=0 is x=2pin,x=pi+2pin