What is the general solution for cos(2x)=0.92 ?

The general solution for cos(2x)=0.92 is x=(0.40271…)/2+pin,x=pi-(0.40271…)/2+pin

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cos(2x)=0.92

cos (2 x) = 0.92

x = \frac{0.40271 \dots}{2} + πn, x = π - \frac{0.40271 \dots}{2} + πn

Solution steps

cos (2 x) = 0.92

Apply trig inverse properties

2 x = arccos (0.92) + 2 πn, 2 x = 2 π - arccos (0.92) + 2 πn

Solve

2 x = arccos (0.92) + 2 πn : x = \frac{arccos ( 0.92 )}{2} + πn

Solve

2 x = 2 π - arccos (0.92) + 2 πn : x = π - \frac{arccos ( 0.92 )}{2} + πn

x = \frac{arccos ( 0.92 )}{2} + πn, x = π - \frac{arccos ( 0.92 )}{2} + πn

Show solutions in decimal form

x = \frac{0.40271 \dots}{2} + πn, x = π - \frac{0.40271 \dots}{2} + πn

cos (4 x) + 1 = 3 sin (2 x), - \frac{π}{2} \leq x \leq \frac{π}{2}

3 - 6 cos (x + \frac{π}{3}) = 0

sin (7.07 t) = 0.5

tan (x) = \frac{1}{3}, 0 \leq x < 2 π

- 2 sin (2 x) = 2 π

What is the general solution for cos(2x)=0.92 ?
The general solution for cos(2x)=0.92 is x=(0.40271…)/2+pin,x=pi-(0.40271…)/2+pin