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Popular Trigonometry >

20sin(t)cos(t)=-4sin(t)

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Solution

20sin(t)cos(t)=−4sin(t)

Solution

t=2πn,t=π+2πn,t=1.77215…+2πn,t=−1.77215…+2πn
+1
Degrees
t=0∘+360∘n,t=180∘+360∘n,t=101.53695…∘+360∘n,t=−101.53695…∘+360∘n
Solution steps
20sin(t)cos(t)=−4sin(t)
Subtract −4sin(t) from both sides20sin(t)cos(t)+4sin(t)=0
Factor 20sin(t)cos(t)+4sin(t):4sin(t)(5cos(t)+1)
20sin(t)cos(t)+4sin(t)
Rewrite 20 as 5⋅4=5⋅4sin(t)cos(t)+4sin(t)
Factor out common term 4sin(t)=4sin(t)(5cos(t)+1)
4sin(t)(5cos(t)+1)=0
Solving each part separatelysin(t)=0or5cos(t)+1=0
sin(t)=0:t=2πn,t=π+2πn
sin(t)=0
General solutions for sin(t)=0
sin(x) periodicity table with 2πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​sin(x)021​22​​23​​123​​22​​21​​xπ67π​45π​34π​23π​35π​47π​611π​​sin(x)0−21​−22​​−23​​−1−23​​−22​​−21​​​
t=0+2πn,t=π+2πn
t=0+2πn,t=π+2πn
Solve t=0+2πn:t=2πn
t=0+2πn
0+2πn=2πnt=2πn
t=2πn,t=π+2πn
5cos(t)+1=0:t=arccos(−51​)+2πn,t=−arccos(−51​)+2πn
5cos(t)+1=0
Move 1to the right side
5cos(t)+1=0
Subtract 1 from both sides5cos(t)+1−1=0−1
Simplify5cos(t)=−1
5cos(t)=−1
Divide both sides by 5
5cos(t)=−1
Divide both sides by 555cos(t)​=5−1​
Simplifycos(t)=−51​
cos(t)=−51​
Apply trig inverse properties
cos(t)=−51​
General solutions for cos(t)=−51​cos(x)=−a⇒x=arccos(−a)+2πn,x=−arccos(−a)+2πnt=arccos(−51​)+2πn,t=−arccos(−51​)+2πn
t=arccos(−51​)+2πn,t=−arccos(−51​)+2πn
Combine all the solutionst=2πn,t=π+2πn,t=arccos(−51​)+2πn,t=−arccos(−51​)+2πn
Show solutions in decimal formt=2πn,t=π+2πn,t=1.77215…+2πn,t=−1.77215…+2πn

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